27=a^2

Solution for 27=a^2 equation:

27=a^2

We move all terms to the left:

27-(a^2)=0

We add all the numbers together, and all the variables

-1a^2+27=0

a = -1; b = 0; c = +27;
Δ = b2-4ac
Δ = 02-4·(-1)·27
Δ = 108
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{108}=\sqrt{36*3}=\sqrt{36}*\sqrt{3}=6\sqrt{3}$
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{3}}{2*-1}=\frac{0-6\sqrt{3}}{-2}
=-\frac{6\sqrt{3}}{-2}
=-\frac{3\sqrt{3}}{-1}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{3}}{2*-1}=\frac{0+6\sqrt{3}}{-2}
=\frac{6\sqrt{3}}{-2}
=\frac{3\sqrt{3}}{-1}
$